Question

CH3—CHBr—COOH与NaOH溶液发生取代反应后，再用盐酸酸化所生成C，C与Ca(OH)2反应的化学方程式

Answer 1

CH3—CHBr—COOH + 2 NaOH === CH3—CH(OH)—COONa + NaBr + H2O(卤代烃水解)
CH3—CH(OH)—COONa + HCl === CH3—CH(OH)—COOH + NaCl（弱酸盐与强酸反应）
2CH3—CH(OH)—COOH + Ca(OH)2 === (CH3—CH(OH)—COO)2Ca + 2 H2O（酸碱中和）

Answer 2

CH3-CHBr-COOH+H2O=CH3-CH(OH)-COOH+HBr
CH3-CH(OH)-COOH+NaOH=CH3-CH(OH)-COONa+H2O(HBr+NaOH=NaBr+H2O)
CH3-CH(OH)-COONa+HCl=NaCl+CH3-CH(OH)-COOH
2CH3-CH(OH)-COOH+Ca(OH)2=Ca(CH3-CH(OH)-COO)2+2H2O
额。。发现还是错了（NaBr+HCl=HBr+NaCl放在第二第三行之间）
然后又因为强酸置弱酸。。所以最后是Ca（Br）2和2CH3-CH(OH)-COOH

Answer 3

CH3-CH(OH)-COONa,CH3-CH(OH)-COOH,[CH3-CH(OH)-COO]2Ca