当x=2,y=3求代数式根号x/根号x-根号y-根号y/根号x+根号y
2个回答
展开全部
解：√x/(√x-√y)-√y/(√x+√y)
=√x(√x+√y)/(x-y)-√y(√x-√y)/(x-y)(分母有理化）
=(x+√xy)/(x-y)-(√xy-y)/(x-y)
=(x+√xy-√xy+y)/(x-y)
=(x+y)/(x-y)
=(2+3)/(2-3)
=-5
=√x(√x+√y)/(x-y)-√y(√x-√y)/(x-y)(分母有理化）
=(x+√xy)/(x-y)-(√xy-y)/(x-y)
=(x+√xy-√xy+y)/(x-y)
=(x+y)/(x-y)
=(2+3)/(2-3)
=-5
已赞过
已踩过<
评论
收起
你对这个回答的评价是？
推荐律师服务：
若未解决您的问题，请您详细描述您的问题，通过百度律临进行免费专业咨询
