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y=sin²2x+sin2xcos2x
=(1-cos4x)/2+1/2*sin4x
=√2/2(sin4x*√2/2-cos4x*√2/2)+1/2
=√2/2(sin4xcosπ/4-cos4xπ/4)+1/2
=√2/2*sin(4x+π/4)+1/2
所以T=2π/4=π/2
=(1-cos4x)/2+1/2*sin4x
=√2/2(sin4x*√2/2-cos4x*√2/2)+1/2
=√2/2(sin4xcosπ/4-cos4xπ/4)+1/2
=√2/2*sin(4x+π/4)+1/2
所以T=2π/4=π/2
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