Question

编写一个显示以下模式的shell脚本，接收一个数字，使用while循环：(1打印1次，2打印2次，3打印3次。。

1
22
333
4444
…………

Answer 1

[root@localhost /]# cat test.sh
#!/bin/sh
i=1
while [ $i -lt 100 ]
do
b=1
while [ $b -le $i ]
do
echo "$i" | tr -d "\n"
b=`expr $b + 1`
done
echo ""
i=`expr $i + 1`
done

[root@localhost /]# ./test.sh
1
22
333
4444
55555
666666
7777777
88888888
999999999
10101010101010101010
1111111111111111111111
121212121212121212121212
13131313131313131313131313
1414141414141414141414141414
151515151515151515151515151515
16161616161616161616161616161616
1717171717171717171717171717171717
181818181818181818181818181818181818
19191919191919191919191919191919191919
2020202020202020202020202020202020202020
212121212121212121212121212121212121212121
22222222222222222222222222222222222222222222
2323232323232323232323232323232323232323232323
242424242424242424242424242424242424242424242424

兄弟，多动点脑子呀。还有，可以就别忘记采纳了。