Question

(x^2+y^2)^2-(z^2-x^2)^2-(y^2+z^2)^2

Answer 1

(x^2+y^2)^2-(z^2-x^2)^2-(y^2+z^2)^2
=(x^2+y^2+z^2-x^2)(x^2+y^2-z^2+x^2)-(y^2+z^2)^2
=(y^2+z^2)(2x^2+y^2-z^2)-(y^2+z^2)^2
=(y^2+z^2)(2x^2+y^2-z^2-y^2-z^2)
=(y^2+z^2)(2x^2-2z^2)
=2(y^2+z^2)(x^2-z^2)
=2(y^2+z^2)(x-z)(x+z)
希望你能看懂，你能明白， 望采纳，赞同

Answer 2

(x^2+y^2)^2-(z^2-x^2)^2-(y^2+z^2)^2
很显然x^4 y^4 已约掉。
=2x^2y^2-2z^4+2x^2z^2-2y^2z^2
=2x^2(y^2+z^2)-2z^2(z^2+y^2)
=2(y^2+z^2)(x-z)(x+z)

Answer 3

(x²+y²)²-(z²-x²)²-(y²+z²)²
=(x²+y²+z²-x²)(x²+y²-z²+x²)-(y²+z²)²
=(y²+z²)(2x²+y²-z²)-(y²+z²)²
=(y²+z²)(2x²+y²-z²-y²-z²)
=(y²+z²)(2x²-2z²)
=2(y²+z²)(x²-z²)
=2(y²+z²)(x-z)(x+z)

Answer 4

你的条件完整吗