Question

lua中写一个函数 随便输入一个日期时间戳 通过函数判断是不是属于当天的日期，该怎么写？

Answer 1

function isToday(timestamp)
local today = os.date("*t")
local secondOfToday = os.time({day=today.day, month=today.month,
year=today.year, hour=0, minute=0, second=0})
if timestamp >= secondOfToday and timestamp < secondOfToday + 24 * 60 * 60 then
return true
else
return false
end
end

print(isToday(os.time({day=17, month=5, year=2012, hour=0, minute=0, second=0})))
print(isToday(os.time({day=17, month=5, year=2012, hour=16, minute=28, second=38})))
print(isToday(os.time({day=17, month=5, year=2012, hour=23, minute=59, second=59})))
print(isToday(os.time({day=16, month=5, year=2012, hour=23, minute=59, second=59})))
print(isToday(os.time({day=18, month=5, year=2012, hour=0, minute=0, second=0})))