Question

第八题，谢谢MATLAB

Answer 1

>> x=-3:0.02:3;

>> y1=2*x+5;

>> y2=x.^2-3*x+1;

>> subplot(1,2,1),plot(x,y1)

>> axis([-3 3 -2 11])

>> title('y=2x+5')

>> subplot(1,2,2),plot(x,y2)

>> axis([-3 3 -2 11])

>> title('y=x^2-3x+1')

追问

你好，怎么统计一个随机矩阵中大于某个值的个数?

Answer 2

x = -3:0.02:3;
y1 = 2*x+5;
y2 = x^2-3*x+1;
subplot(2,1,1)
plot(x,y1);
axis([-3,3,-5,19])
subplot(x,y2);
plot(x,y2)
axis([-3,3,-5,19])