Question

1十2十3……十100表示连续自然数的和,为了简便我们用求和的符号计算，符号上面2014，下面n

1，旁边n(n+1）分之1，

Answer 1

∑<n=1, 2014> 1/[n(n+1)]
= ∑<n=1, 2014> [1/n-1/(n+1)]
= 1-1/2+1/2-1/3+1/3-1/4+......+1/2014-1/2015
= 1-1/2015 = 2014/2015.