(1)计算:(x+1)0-12+|?3|(2)解方程:2x2-2x-1=0(3)化简:x?1x2?1-xx2?x
(1)计算:(x+1)0-12+|?3|(2)解方程:2x2-2x-1=0(3)化简:x?1x2?1-xx2?x....
(1)计算:(x+1)0-12+|?3|(2)解方程:2x2-2x-1=0(3)化简:x?1x2?1-xx2?x.
展开
1个回答
展开全部
(1)原式=1-2
+
=1-
;
(2)∵2x2-2x-1=0的二次项系数a=2,一次项系数b=-2,常数项c=-1,
∴x=
=
=
,
∴x1=
,x2=
3 |
3 |
3 |
(2)∵2x2-2x-1=0的二次项系数a=2,一次项系数b=-2,常数项c=-1,
∴x=
?b±
| ||
2a |
2±
| ||
4 |
1±
| ||
2 |
∴x1=
1+
| ||
2 |
1?
|