谁给个easyui里面datagrid的例子，用json加载的例子

 我来答

1个回答

#热议# 空调使用不当可能引发哪些疾病？

紫血M恶魔
推荐于2016-10-21 · TA获得超过104个赞

知道小有建树答主

回答量：118

采纳率：0%

帮助的人：114万

我也去答题访问个人页

关注

展开全部

<!DOCTYPE html>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>Complex DataGrid - jQuery EasyUI Demo</title>
<link rel="stylesheet" type="text/css" href="../themes/default/easyui.css">
<link rel="stylesheet" type="text/css" href="../themes/icon.css">
<link rel="stylesheet" type="text/css" href="demo.css">
<script type="text/javascript" src="../jquery-1.8.0.min.js"></script>
<script type="text/javascript" src="../jquery.easyui.min.js"></script>
<script>
$(function(){
$('#test').datagrid({
title:'My DataGrid',
iconCls:'icon-save',
width:700,
height:350,
nowrap: true,
autoRowHeight: false,
striped: true,
collapsible:true,
url:'datagrid_data.json',
sortName: 'code',
sortOrder: 'desc',
remoteSort: false,
idField:'code',
frozenColumns:[[
{field:'ck',checkbox:true},
{title:'Code',field:'code',width:80,sortable:true}
]],
columns:[[
{title:'Base Information',colspan:3},
{field:'opt',title:'Operation',width:100,align:'center', rowspan:2,
formatter:function(value,rec){
return '<span style="color:red">Edit Delete</span>';
}
}
],[
{field:'name',title:'Name',width:120},
{field:'addr',title:'Address',width:220,rowspan:2,sortable:true,
sorter:function(a,b){
return (a>b?1:-1);
}
},
{field:'col4',title:'Col41',width:150,rowspan:2}
]],
pagination:true,
rownumbers:true,
toolbar:[{
id:'btnadd',
text:'Add',
iconCls:'icon-add',
handler:function(){
$('#btnsave').linkbutton('enable');
alert('add')
}
},{
id:'btncut',
text:'Cut',
iconCls:'icon-cut',
handler:function(){
$('#btnsave').linkbutton('enable');
alert('cut')
}
},'-',{
id:'btnsave',
text:'Save',
disabled:true,
iconCls:'icon-save',
handler:function(){
$('#btnsave').linkbutton('disable');
alert('save')
}
}]
});
var p = $('#test').datagrid('getPager');
$(p).pagination({
onBeforeRefresh:function(){
alert('before refresh');
}
});
});
function resize(){
$('#test').datagrid('resize', {
width:700,
height:400
});
}
function getSelected(){
var selected = $('#test').datagrid('getSelected');
if (selected){
alert(selected.code+":"+selected.name+":"+selected.addr+":"+selected.col4);
}
}
function getSelections(){
var ids = [];
var rows = $('#test').datagrid('getSelections');
for(var i=0;i<rows.length;i++){
ids.push(rows[i].code);
}
alert(ids.join(':'));
}
function clearSelections(){
$('#test').datagrid('clearSelections');
}
function selectRow(){
$('#test').datagrid('selectRow',2);
}
function selectRecord(){
$('#test').datagrid('selectRecord','002');
}
function unselectRow(){
$('#test').datagrid('unselectRow',2);
}
function mergeCells(){
$('#test').datagrid('mergeCells',{
index:2,
field:'addr',
rowspan:2,
colspan:2
});
}
</script>
</head>
<body>
<h2>Complex DataGrid</h2>
<div class="demo-info">
<div class="demo-tip icon-tip"></div>
<div>Click the button to do actions with datagrid.</div>
</div>

<div style="margin:10px 0;">
<a href="#" onclick="getSelected()">GetSelected</a>
<a href="#" onclick="getSelections()">GetSelections</a>
<a href="#" onclick="selectRow()">SelectRow</a>
<a href="#" onclick="selectRecord()">SelectRecord</a>
<a href="#" onclick="unselectRow()">UnselectRow</a>
<a href="#" onclick="clearSelections()">ClearSelections</a>
<a href="#" onclick="resize()">Resize</a>
<a href="#" onclick="mergeCells()">MergeCells</a>
</div>

<table id="test"></table>

</body>
</html>

追问

url：异步加载json需要开启服务器吗，还是直接写个json文件放进来就行了

追答

要服务器，url就是一个请求，后台处理请求后返回json格式的数据就行了

本回答被提问者和网友采纳

已赞过 已踩过<

评论收起

推荐律师服务：若未解决您的问题，请您详细描述您的问题，通过百度律临进行免费专业咨询

谁给 个easyui里面datagrid的例子，用json加载 的例子

其他类似问题

为你推荐：

谁给个easyui里面datagrid的例子，用json加载的例子