初一数学:几道因式分解的计算题~~~~
要求有详细解答过程,不能只有答案或笼统概括(x²-y²-2x+1)÷(x+y-1)=(x四次方-2x²+1)÷(x²+2x+1)=...
要求有详细解答过程,不能只有答案或笼统概括
(x²-y²-2x+1)÷(x+y-1)
=
(x四次方-2x²+1)÷(x²+2x+1)
=
(a四次方-16)÷(a-2)
= 展开
(x²-y²-2x+1)÷(x+y-1)
=
(x四次方-2x²+1)÷(x²+2x+1)
=
(a四次方-16)÷(a-2)
= 展开
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1.(X-1)2-Y2/X+Y-1 =(X+Y-1)(X-Y-1)/(X+Y-1) =X-Y-1
2.(X2-1)2/(X+1)2 =(X+1)2(X-1)2/(X+1)2 =(X+1)2
3.(a2-4)(a2+4)/a-2 =(a+2)(a-2)(a2+4)/(a-2) =(a2+4)(a+2) 字母旁的是二次方。希望能帮助你。这些不难,多背背平方差公式,完全平方和公式就行了
2.(X2-1)2/(X+1)2 =(X+1)2(X-1)2/(X+1)2 =(X+1)2
3.(a2-4)(a2+4)/a-2 =(a+2)(a-2)(a2+4)/(a-2) =(a2+4)(a+2) 字母旁的是二次方。希望能帮助你。这些不难,多背背平方差公式,完全平方和公式就行了
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(x²-y²-2x+1)÷(x+y-1)
=[(x-1)²-y²]÷(x+y-1)
=(x+y-1)(x-y-1)÷(x+y-1)
=x-y-1
(x^4-2x²+1)÷(x²+2x+1)
=(x²-1)²÷(x+1)²
=(x+1)²(x-1)²÷(x+1)²
=(x-1)²
(a^4-16)÷(a-2)
=(a²+4)(a²-4)÷(a-2)
=(a²+4)(a+2)(a-2)÷(a-2)
=(a²+4)(a+2)
=[(x-1)²-y²]÷(x+y-1)
=(x+y-1)(x-y-1)÷(x+y-1)
=x-y-1
(x^4-2x²+1)÷(x²+2x+1)
=(x²-1)²÷(x+1)²
=(x+1)²(x-1)²÷(x+1)²
=(x-1)²
(a^4-16)÷(a-2)
=(a²+4)(a²-4)÷(a-2)
=(a²+4)(a+2)(a-2)÷(a-2)
=(a²+4)(a+2)
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=(x²-2x+1-y²)÷(x+y-1)
=((x-1)²-y²)÷(x+y-1)
=(x-1-y)(x-1+y)÷(x+y-1)
=x-1-y
=((x²)²-2x²+1))÷(x+1)²
=(x²-1)²÷(x+1)²
=(x+1)(x-1)÷(x+1)²
=x-1/x+1
=((a²)²-(2²)²))÷(a-2)
=(a²-2²)(a²+2²))÷(a-2)
=(a+2)(a-2)(a²+4)÷(a-2)
=(a-2)(a²+4)
=((x-1)²-y²)÷(x+y-1)
=(x-1-y)(x-1+y)÷(x+y-1)
=x-1-y
=((x²)²-2x²+1))÷(x+1)²
=(x²-1)²÷(x+1)²
=(x+1)(x-1)÷(x+1)²
=x-1/x+1
=((a²)²-(2²)²))÷(a-2)
=(a²-2²)(a²+2²))÷(a-2)
=(a+2)(a-2)(a²+4)÷(a-2)
=(a-2)(a²+4)
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1原式=(x²-2x-1-y²)/(x+y+1)=((x-1)²-y² )/(x+y-1)=(x-y-1)
2 原式=(x ²-1)²/(x+1)²=(x-1)²(x+1)²/(x-1)²=x²+2x+1
3原式=(a²-4)(a²+4)/(a-2)=(a-2)(a+2)(a²+4)/(a-2)=(a+2)(a²+4)
2 原式=(x ²-1)²/(x+1)²=(x-1)²(x+1)²/(x-1)²=x²+2x+1
3原式=(a²-4)(a²+4)/(a-2)=(a-2)(a+2)(a²+4)/(a-2)=(a+2)(a²+4)
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