怎么解，求过程！！！！！？？ 10
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解：只需f(-0)=f(0)=f(+0)也即
lim f(x)=f(0)=a=lim f(x)
x->-0 x->+0
lim f(x)=lim sinbx/x=lim [sinbx/(bx)]*b=1*b=b
x->-0 x->-0 x->-0
lim f(x)=lim [(1+x)/(1-x)]^(1/x)=
x->+0
lim [(1+2x/(1-x)]^(1/x)=
x->+0
lim [(1+2x/(1-x)]^[(1-x)/2x*2x/(1-x)*(1/x)]=
x->+0
lim [(1+2x/(1-x)]^[(1-x)/2x*2/(1-x)]=
x->+0
lim {[(1+2x/(1-x)]^[(1-x)/2x]}^[2/(1-x)]=
x->+0
lim e^[2/(1-x)]= e^2
x->+0
故a=b=e^2
lim f(x)=f(0)=a=lim f(x)
x->-0 x->+0
lim f(x)=lim sinbx/x=lim [sinbx/(bx)]*b=1*b=b
x->-0 x->-0 x->-0
lim f(x)=lim [(1+x)/(1-x)]^(1/x)=
x->+0
lim [(1+2x/(1-x)]^(1/x)=
x->+0
lim [(1+2x/(1-x)]^[(1-x)/2x*2x/(1-x)*(1/x)]=
x->+0
lim [(1+2x/(1-x)]^[(1-x)/2x*2/(1-x)]=
x->+0
lim {[(1+2x/(1-x)]^[(1-x)/2x]}^[2/(1-x)]=
x->+0
lim e^[2/(1-x)]= e^2
x->+0
故a=b=e^2
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