Question

matlab多元函数求最小值问题

matlab求r =1/(9-j)*(i^2+81-18*j+j^2)^(1/2)*(38/5-19/20*fix(j)+1/20*(8-fix(j))^2)+(fix(j)+1-j)/(9-j)*(i^2+81-18*j+j^2)^(1/2)*(9/5-1/10*fix(j))+(j^2-2*j*n+n^2+m^2-2*m*i+i^2)^(1/2)/(j-n)*(-19/20*fix((n*i-m*j)/(i+n-j-m))+19/20*fix(j)+1/20*(9-fix((n*i-m*j)/(i+n-j-m)))^2-1/20*(9-fix(j))^2)+(j-fix(j))/(j-n)*(j^2-2*j*n+n^2+m^2-2*m*i+i^2)^(1/2)*(9/5-1/10*fix(j))+(fix(m-(fix((n*i-m*j)/(i+n-j-m))-n)*(m-i)/(j-n))+1-m+(fix((n*i-m*j)/(i+n-j-m))-n)*(m-i)/(j-n))*(j^2-2*j*n+n^2+m^2-2*m*i+i^2)^(1/2)/(m-i)*(9/5-1/10*fix((n*i-m*j)/(i+n-j-m)))+(j^2-2*j*n+n^2+m^2-2*m*i+i^2)^(1/2)/(m-i)*(fix(j)-19/20*fix(m-(fix((n*i-m*j)/(i+n-j-m))-n)*(m-i)/(j-n))-1+1/20*(9-fix(m-(fix((n*i-m*j)/(i+n-j-m))-n)*(m-i)/(j-n)))^2-1/20*(9-fix(m))^2-1/20*fix(m))+(m-fix(j))/(m-i)*(j^2-2*j*n+n^2+m^2-2*m*i+i^2)^(1/2)*(9/5-1/10*fix(j))+(-18*m+81+n^2+m^2)^(1/2)/(9-m)*(38/5-19/20*fix(m)+1/20*(8-fix(m))^2)+(fix(m)+1-m)/(9-m)*(-18*m+81+n^2+m^2)^(1/2)*(9/5-1/10*fix(m)) 的最小值 j范围[5,8] i范围[9-j,j]

Answer 1

fmincon 求吧