Question

观察下列各式,1/6=1/2*3=1/2-1/3;1/12=1/3*4=1/3-1/4:1/20=1/4*5=1/4-1/5;1/30=1/

用上面的规律解方程：1/（x-2)（x-3)-1/(x-1)(x-3)+1/(x-1)(x-2)
不要用其他人的回答，要过程

Answer 1

根据帆氏规脊颂律方程态野散=1/(x-2)-1/(x-3)-[1/(x-1)-1/(x-3)]+1/(x-1)-1/(x-2)=0

Answer 2

1/（x-2)（x-3)-1/(x-1)(x-3)+1/(x-1)(x-2)
=1/（源李x-2)-1/（x-3)-1/(x-1)+1/凳裂(x-3)+1/(x-1)-1/枣裂闭(x-2)
=0

追问

1/(x-1)(x-3)怎么化成1/(x-1)+1/(x-3）
还有1/(x-1)(x-2)
应该是)1/(x-2)-1/(x1)吧，1/(x-2)小于1/(x1)，不是要放在前面吗

追答

哦，对不起
1/（x-2)（x-3)-1/(x-1)(x-3)+1/(x-1)(x-2)
=1/（x-3)-1/（x-2)-1/2[1/(x-3)-1/(x-1)]+1/(x-2)-1/(x-1)
=1/（x-3)-1/（x-2)-1/2(x-3)+1/2(x-1)+1/(x-2)-1/(x-1)
=1/2(x-3)-1/2(x-1)
=1/(x-1)(x-3)