Question

[a²-4/a²-4a+4-1/2-a]/2/a²-2a

帮帮忙啊 今天就这个题弄死我了

Answer 1

x=a
则a²+3a-2=0
a²+3a=2

原式=[(a+2)(a-2)/(a-2)²+1/(a-2)]×a(a-2)/2
=[(a+2)/(a-2)+1/(a-2)]×a(a-2)/2
=(a+2+1)/(a-2)×a(a-2)/2
=a(a+3)/2
=(a²+3a)/2
=2/2
=1