Question

(m-3)²分之m-4×（1+m²-8m+16分之14m-7）÷m-3分之1等于多少？步骤

快呀

Answer 1

解：
原式=[(m-4)/(m-3)²]×[1+(14m-7)/(m²-8m+16)]÷[1/(m-3)]
=[(m-4)/(m-3)²]×[(m²-8m+16)/(m²-8m+16)+(14m-7)/(m²-8m+16)]×(m-3)
=[(m-4)/(m-3)²]×[(m²-8m+16+14m-7)/(m²-8m+16)]×(m-3)
=[(m-4)/(m-3)²]×[(m²-6m+9)/(m²-8m+16)]×(m-3)
=[(m-4)/(m-3)²]×[(m-3)²/(m-4)²]×(m-3)
=(m-3)/(m-4)