如何设计实现一个LRU Cache
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之前,在LeetCode上看到一个LRU Cache实现的题目,题目描述是这样的:
Design and implement a data structure for Least Recently Used (LRU) cache. It should support the following operations: get and set.
get(key) - Get the value (will always be positive) of the key if the key exists in the cache, otherwise return -1.
set(key, value) - Set or insert the value if the key is not already present. When the cache reached its capacity, it should invalidate the least recently used item before inserting a new item.
简单的说,就是保证基本的get和set的功能的同时,还要保证最近访问(get或put)的节点保持在限定容量的Cache中,如果超过容量则应该把LRU(近期最少使用)的节点删除掉。
Design and implement a data structure for Least Recently Used (LRU) cache. It should support the following operations: get and set.
get(key) - Get the value (will always be positive) of the key if the key exists in the cache, otherwise return -1.
set(key, value) - Set or insert the value if the key is not already present. When the cache reached its capacity, it should invalidate the least recently used item before inserting a new item.
简单的说,就是保证基本的get和set的功能的同时,还要保证最近访问(get或put)的节点保持在限定容量的Cache中,如果超过容量则应该把LRU(近期最少使用)的节点删除掉。
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