Question

C++ 求1+2+3+…+100的值 (分别用while语句和for 语句实现)

例子：
：#include "stdio.h"
main()
{
int number, sum;
sum=0;
number=1;
while (number<=100)
{
sum=sum+number;
number=number+1;
}
printf("%d",sum);
但是这个程序已经被用了，换一个。

Answer 1

while语句实现，代码如下：

for语句实现，代码如下：

Answer 2

用for写
#include "stdio.h"
void main()
{
int sum=0;
for(int i=1; i<=100;i++)
sum=sum+i;
printf("the result is " "%d",sum);
printf("\n");
}
用while写
#include "stdio.h"
main()
{
int number, sum;
sum=0;
number=1;
while (number<=100)
{
sum=sum+number;
number++;
}
printf("%d",sum);
printf("\n");
}
楼主觉得好的请采纳，谢谢啊！

Answer 3

#include "stdio.h"
void main(){
int sum=0;
for(int i=1; i<=100;i++)
sum+=i;
printf("%d",sum);
}

Answer 4

#include <iostream>
using namespace std;

template <class T>
T Sum_implemented_by_for(T num)
{
T sum = 0;
for(T i=1;i<=num;i+=1){
sum+=i;
}
return sum;
}

template <class T>
T Sum_implemented_by_while(T num)
{
T sum = 0;
T i=0;
while(i<num){
sum+=(++i);
}
return sum;
}

void main()
{
cout<<"for cycle to ge sum: "<<Sum_implemented_by_for(100)<<endl;
cout<<"while cycle to ge sum: "<<Sum_implemented_by_while(100)<<endl;

system("pause");
}