Question

java biginteger怎么比较大小

Answer 1

compareTo方法来比较，小于则返回-1，等于则返回0，大于则返回1

BigInteger a1 = new BigInteger("1");
BigInteger a2 = new BigInteger("2");
a1.compareTo(a2);

下面的例子显示math.BigInteger.compareTo()方法的用法

package com.yiibai;import java.math.*;public class BigIntegerDemo {public static void main(String[] args) {

// create 2 BigInteger objects
BigInteger bi1, bi2;

bi1 = new BigInteger("6");
bi2 = new BigInteger("3");

// create int object
int res;

// compare bi1 with bi2
res = bi1.compareTo(bi2);

String str1 = "Both values are equal ";
String str2 = "First Value is greater ";
String str3 = "Second value is greater";

if( res == 0 )
System.out.println( str1 );
else if( res == 1 )
System.out.println( str2 );
else if( res == -1 )
System.out.println( str3 );
}}

让我们编译和运行上面的程序，这将产生以下结果：

First Value is greater

Answer 2

compareTo方法来比较，小于则返回-1，等于则返回0，大于则返回1

BigInteger a1 = new BigInteger("1");
BigInteger a2 = new BigInteger("2");
a1.compareTo(a2);

Answer 3

java bigintic void main(String[] args) { BigIntege