Question

c语言改错题，急！！！！

#include <stdio.h>
#include <math.h>

main ()
{
double a, b, c, s, ss;
printf("Please input the edges of the triangle:');
scanf("%f,%f,%f", a, b, c);

if (a + b < c && a + c > b && b + c > a)
s = (a + b + c)%2;
ss = sqrt(s*(s-a)*(s-b)*(s-c);
printf("The area of this triangle is %.2lf", ss);
else
{
printf("%lf, %lf, %lf can not form a triangle!!", a, b, c);
}
}
3-6个错

Answer 1

#include <stdio.h>
#include <math.h>

int main ()
{
double a, b, c, s, ss;
printf("Please input the edges of the triangle:");
//printf("Please input the edges of the triangle:");
scanf("%f,%f,%f", &a, &b, &c);
//scanf("%f,%f,%f", &a, &b, &c);

if (a + b < c && a + c > b && b + c > a)
s = (a + b + c)%2;
//double双精度不可以使用取余的操作
ss = sqrt(s*(s-a)*(s-b)*(s-c));
//ss = sqrt(s*(s-a)*(s-b)*(s-c));
printf("The area of this triangle is %.2lf", ss);
else
{
printf("%lf, %lf, %lf can not form a triangle!!", a, b, c);
}
//else和if无法匹配了！这个要根据你的语义修改
}

Answer 2

#include <stdio.h>
#include <math.h>

main ()
{
double a, b, c, s, ss;
printf("Please input the edges of the triangle:"); 注意双引号" "
scanf("%lf,%lf,%lf", &a,& b,& c); 因为是double，所以输入应改为%lf,虽然语法没错，但结果有误。还有别忘了地址运算符&

if (a + b > c && a + c > b && b + c > a) 三角形里面应该是任何两边大于第三边
s = (a + b + c)/2; %这是求余运算符，此时应该用整除运算符/
ss = sqrt(s*(s-a)*(s-b)*(s-c)); 少了）
printf("The area of this triangle is %10.2lf", ss); 10.2代表是输出的数据共占10列，小数点有2位，不能直接写.2，这是语法错误
else
{
printf("%lf, %lf, %lf can not form a triangle!!", a, b, c);
}
}
C语言在于多多上机练习！加油了！

Answer 3

printf("Please input the edges of the triangle:');
改成;printf("Please input the edges of the triangle:");

scanf("%f,%f,%f", a, b, c);
改成;scanf("%f,%f,%f",&a,&b,&c);

if (a + b < c && a + c > b && b + c > a)
s = (a + b + c)%2;
ss = sqrt(s*(s-a)*(s-b)*(s-c);
printf("The area of this triangle is %.2lf", ss);
改成：if (a + b < c && a + c > b && b + c > a)
{
s = (a + b + c)%2;
ss = sqrt(s*(s-a)*(s-b)*(s-c));
printf("The area of this triangle is %.2lf", ss);
}

这句理解不了 s = (a + b + c)%2;

追问

第1题：编程题1（30分）
题目描述：输入任意一个字符串，编程求出该字符串中字母l出现的总次数。
例如，输入：hello world
输出：3

第2题：编程题2
题目描述：编写程序，从键盘上输入10个整数，然后删除其中的最小值和最大值，最后输出删除前后的数组。

追答

1、
#include
#define MAX 40
void main()
{
char a[MAX];
int count=0,i;
char l='l';
printf("输入字符串:");
gets(a);
for(i=0;a[i]!='\0';i++)
{

if(a[i]=='l')
{
count++;
}
}
printf("字符串中字母l出现的总次数:%d\n",count);
}
2、要用指针，不太会啊

Answer 4

1、输入没有地址符&,对应的格式符有些编译系统也不能这样写
2、 ss = sqrt(s*(s-a)*(s-b)*(s-c);少一边括号；
3、if (a + b < c && a + c > b && b + c > a)中a+b<c应该是a+b>c
4、if语句下面的两条语句应该合成复合语句

Answer 5

#include "stdafx.h"
#include<string.h>
#include <math.h>
int _tmain(int argc, _TCHAR* argv[])
{

double a, b, c, s, ss;
printf("Please input the edges of the triangle:");
scanf("%f,%f,%f", &a, &b, &c);

if (a + b < c && a + c > b && b + c > a)
{
s = (int)(a + b + c) % 2;
ss = sqrt(s*(s-a)*(s-b)*(s-c));
printf("The area of this triangle is %.2lf", ss);
}
else
{
printf("%lf, %lf, %lf can not form a triangle!!", a, b, c);
}
getchar();
return 0;
}
你自己对照一下

追问

不得增加删除行，不得更改结构

追答

double a, b, c, s, ss;
printf("Please input the edges of the triangle:");//后面是引号，不是单引号
scanf("%f,%f,%f", &a, &b, &c);//这里要取地址符scanf("%f,%f,%f", &a, &b, &c);

if (a + b b && b + c > a)
{
s = (int)(a + b + c)%2; //类型转化问题,double类型与整型要转化
ss = sqrt(s*(s-a)*(s-b)*(s-c));//少括号
printf("The area of this triangle is %.2lf", ss);
}
else //对于else而言if是不可见的，所以要加上括号
{
printf("%lf, %lf, %lf can not form a triangle!!", a, b, c);
}