Question

Linux下如何获取FTP文件名和大小？

Linux下如何获取FTP文件名和大小？我们是先用grep获取FTP上最新的文件夹，然后要获取这个文件夹里面所有.xml文件名和它们的大小，然后写入download.log.接着又再扫描本地的文件名和大小与download.log比较来确认是不是下载完，下载完就删除服务器的文件夹。.sh脚本要怎么写？？
mhost=scdftp01
muser=hphcws1
mpass=3dfkp12p
mremoteloc=/data/hphmns1/hphcwsa
mlocalloc=/sw/users/cwsdev/java/apache-tomcat-5.5.34/webapps/webdav/news
mworkloc=/sw/users/cwsdev/download
mtmplog=download.log
mstart=`date`

echo "Download File Start on $mstart ......"

cd $mworkloc

ftp -n $mhost << END_SCRIPT
quote USER $muser
quote PASS $mpass
cd $mremoteloc
ls -l $mtmplog
quit
END_SCRIPT

echo "-->finding the latest folder ...."

mfoldername=`cat $mworkloc/$mtmplog | grep '^d' | cut -c55- | sort -n | sed -n '$p'`

echo "-->target folder : $mfoldername"

echo "-->creating local folder : $mfoldername"

cd $mlocalloc
if [ -d $mfoldername ]
then
echo "----->folder [$mfoldername] already exists"
else
mkdir $mfoldername
echo "----->local folder [$mfoldername] created"
fi
cd $mfoldername

echo "-->downloading files ...."

ftp -n -i $mhost << END_SCRIPT_2
quote USER $muser
quote PASS $mpass
cd $mremoteloc
cd $mfoldername

Answer 1

path='' #这里的$1,换成你需要的路径名，或者你不换，通过shell的参数传入
for dirlist in $(find ${path} -name *.xml)
do
echo ${dirlist}
查找，删除，比较都在这做
done

追问

能写详细点吗谢谢
1. Get the name and size of all the xml files in the directory and output into
2. Get the xml files
3. Compare the name and size in are exists and equal to the files downloaded in the local directory
4. Delete the xml files and folder in the ftp if Point 3 is True
在“
mget *.xml
quit
END_SCRIPT_2”前加上。