Question

bat如何获取字符串中某个字符的多少

Answer 1

@echo off & setlocal enabledelayedexpansion 

set "Str=BDQABDAWBFANFAWNFANF"

for /l %%a in (0,1,50) do (
	if "!Str:~%%a,1!" equ "A" set/a Sumstr+=1
)

echo 在字符串:!Str!中共有!Sumstr!个A字符

pause>nul

Answer 2

' 2>nul&cls&set /p input=输入字符串:&set /p find=输入查找的字符串:&call echo %%input%%---%%find%%|cscript -nologo -e:vbs "%~0"&pause&exit
set regexp=new regexp
with regexp
	.global=-1:
	read=wsh.stdin.readline
	.pattern="(.*)---(.*)"
	find=.replace(read,"$2")
	read=.replace(read,"$1")
	.pattern=find
	wsh.echo .execute(read).count
end with