Question

求三角函数值：1. sin3份之4派·cos(-6份之25派)·tan4分之5派

Answer 1

sin(4π/3)=－sin(π/3)=－√3/2
cos(－25π/6)=cos(25π/6)=cos(π/6)=√3/2
tan(5π/4)=tan(π/4)=1
则原式=[－√3/2]×[√3/2]×1=－3/4

Answer 2

sin(4π/3)=－sin(π/3)=－√3/2
cos(－25π/6)=cos(25π/6)=cos(π/6)=√3/2
tan(5π/4)=tan(π/4)=1
原始=[－√3/2]×[√3/2]×1=－3/4

Answer 3

化简可得：=-sin(π/3)*cos(π/6)*(-)tan(π/4)
=-√3/2*√3/2*1
=-3/2

Answer 4

化简可得：=-sin(π/3)*cos(π/6)*(-)tan(π/4)
=-√3/2*√3/2*1
=-3/4