Question

(x+1)(x的平方+1)(x-1)(x的4次方+1)

Answer 1

x的八次方。先算(x+1)(x-1)得x的平方-1，然后（x的平方+1）乘以（x的平方-1）得（x的四次方-1）再用（x的四次方-1）乘以（x的四次方+1）得x的八次方。

Answer 2

(x+1)(x的平方+1)(x-1)(x的4次方+1)
=(x-1)(x+1)(x的平方+1)(x的4次方+1)
=(x²-1)(x²+1)(x^4+1)
=(x^4-1)(x^4+1)
=x^8-1
即x的8次方-1

Answer 3

(x+1)(x^2+1)(x-1)(x^4+1)
=[(x+1)(x-1)](x^2+1)(x^4+1)
=(x^2-1)(x^2+1)(x^4+1)
=(x^4-1)(x^4+1)
=x^8-1

Answer 4

(x+1)(x^2+1)(x-1)(x^4+1)
=(x+1)(x-1)(x^2+1)(x^4+1)
=(x^2-1)(x^2+1)(x^4+1)
=(x^4-1)(x^4+1)
=x^8-1

Answer 5

(x+1)( x^2+1)(x-1)( x^4+1)= (x+1) (x-1) (x^2+1) (x^4+1)= (x^2-1) (x^2+1) (x^4+1)= (x^4-1) (x^4+1)= (x^8-1)