Question

C语言编写程序求和（急）

Answer 1

#include <stdio.h>

int main(void)
{
double sum = 0;
int i;

for (i = 1; i <= 50; i++)
sum += i;
for (i = 1; i <= 10; i++) {
sum += i * i * i;
sum += 1.0 / (i * i);
}
printf("sum = %lf\n", sum);
return 0;
}

Answer 2

#include <iostream>
using namespace std;
int main()
{
double sum = 0.0;
for (int k = 1; k <= 50; k++)
{
sum +=k;
}
for (int k = 1; k <= 10; k++)
{
sum +=k*k*k;
}
for (int k = 1; k <= 10; k++)
{
sum +=1.0/double(k*k);
}
cout<<sum<<endl;
return 0;
}

Answer 3

#include<stdio.h>
void main()
{
int i,j,sum1,sum_2;
float k,sum_3,sum;
for(i=1,sum_1=0;i<=50;i++)
sum_1=i+sum_1;
for(j=1,sum_2=0;j<=10;j++)
sum_2=i*i*i+sum_2;
for(k=1.0,sum_3=0.0;k<=10.0;k++)
sum_3=1.0/(k*k)+sum_3;
sum=sum_1+su_2+sum_3;
printf(sum="%.2f",sum);
}

Answer 4

#include <stdio.h>
#include <conio.h>

int main(void)
{
int k;
double sum = 0;

for (k = 1; k <= 50; k++)
sum += k;
for (k = 1; k <= 10; k++)
{
sum += k * k * k;
sum += 1.0f / (k * k);
}
printf("lf\n", sum);
}