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8. ∫∫<D>x^2y^2dxdy = ∫<0, 1>y^2dy∫<-√y, √y>x^2dx
= 2∫<0, 1>y^2dy∫<0, √y>x^2dx = (2/3)∫<0, 1>y^2dy[x^3]∫<0, √y>
= (2/3)∫<0, 1>y^2[y^(3/2)]dy = (2/3)∫<0, 1>[y^(7/2)]dy
= (2/3)(2/9)[y^(9/2)]<0,1> = 4/27
= 2∫<0, 1>y^2dy∫<0, √y>x^2dx = (2/3)∫<0, 1>y^2dy[x^3]∫<0, √y>
= (2/3)∫<0, 1>y^2[y^(3/2)]dy = (2/3)∫<0, 1>[y^(7/2)]dy
= (2/3)(2/9)[y^(9/2)]<0,1> = 4/27
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应该是4/27
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