这初一数学题怎么做 10
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3x²y-[2xy-2×(xy-3/2x²y)+x²y²]
=3x²y-[2xy-（2xy-3x²y）+x²y²]
=3x²y-[2xy-2xy+3x²y+x²y²]
=3x²y-[3x²y+x²y²]
=3x²y-3x²y-x²y²
=-x²y²
-x²y²=-3²×1/3²=-9×1/9=-1
=3x²y-[2xy-（2xy-3x²y）+x²y²]
=3x²y-[2xy-2xy+3x²y+x²y²]
=3x²y-[3x²y+x²y²]
=3x²y-3x²y-x²y²
=-x²y²
-x²y²=-3²×1/3²=-9×1/9=-1
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