己知|x+1|=4,(y+2)的平方=4,求x+y的值.
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|x + 1| = 4, x + 1 = ±4, x = 3, x = -5
(y + 2)² = 4, y + 2 = ±2, y = 0, y = -4
(1) x = 3, y = 0, x + y = 3
(2) x = 3, y = -4, x + y = -1
(3) x = -5, y = -4, x + y = -9
(4) x = -5, y = 0, x + y = -5
(y + 2)² = 4, y + 2 = ±2, y = 0, y = -4
(1) x = 3, y = 0, x + y = 3
(2) x = 3, y = -4, x + y = -1
(3) x = -5, y = -4, x + y = -9
(4) x = -5, y = 0, x + y = -5
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