Question

spring mvc框架中，web.xml的url-pattern采用/app/*形式拦截请求，页面应该如何导入css、js？

Answer 1

<filter>
<filter-name>SecurityFilter</filter-name>
<filter-class>com.analytics.common.filter.SecurityFilter</filter-class>
<init-param>
<param-name>checkSessionKey</param-name>
<param-value>user</param-value>
</init-param>
<init-param>
<param-name>redirectURL</param-name>
<param-value>/login</param-value>
</init-param>
<init-param>
<description>/img/*,/resource/* 不需要过滤的目录,目前只支持一级目录.uri可以写多个;号隔开</description>
<param-name>notCheckURLList</param-name>
<param-value>/img/*;/resource/*;/login</param-value>
</init-param>
</filter>

<filter-mapping>
<filter-name>SecurityFilter</filter-name>
<url-pattern>*.jsp</url-pattern>
</filter-mapping>
<filter-mapping>
<filter-name>SecurityFilter</filter-name>
<url-pattern>*</url-pattern>
</filter-mapping>
filter加一个
<param-name>notCheckURLList</param-name>
就可以了，具体目录是下边这样的
<param-value>/img/*;/resource/*;/login</param-value>

Answer 2

以前怎么导入就怎么导入