Question

如图,射线OB和射线OE分别是∠AOC和∠DOF的角平分线。已知∠BOF=m°，∠COD=n°

试用含有m、n来表示∠AOF的度数______

Answer 1

因为∠AOC+∠DOF
=2∠BOC+2∠DOE
=2(∠BOC+∠DOE)
=2(∠BOE-∠COD)
=2(m-n)
所以∠AOF=∠AOC+∠DOF+∠COD=2(m-n)+n=2m-2n+n=2m+