Question

计算(根号2+2倍根号3-根号6)(根号2-2倍根号3+根号6)，要步骤．急急急！！！麻烦了！

Answer 1

(根号2+2倍根号3-根号6)(根号2-2倍根号3+根号6)
=[根号2+(2倍根号3-根号6)]*[根号2-(2倍根号3-根号6)]
=(根号2)²-(2倍根号3-根号6)²
=2- 3(2-根号2)²
=2-3(6-4根号2)
=2-18+12根号2
=-16+12根号2

Answer 2

(√2+2√3-√6)*(√2-2√3+√6)
=[√2+(2√3-√6)]*[√2-(2√3-√6)]
=(√2)^2-(2√3-√6)^2
=2-(12-12√2+6)
=12√2-16