Question

输入一串字符,计算其中字母的个数

#include <stdio.h>
#include <string.h>
#define N 81
void main()
{
char ch[N];
int i,count=0;
puts("请输入一串字符：");
_____________________ /*提示：使用字符串输入函数*/
for(i=0;i<strlen(ch);i++)
if(_____________________________________)
count++;
printf("字母个数为：%d \n", count);
}

Answer 1

#include <stdio.h>
#include <string.h>
#define N 81
void main()
{
char ch[N];
int i,count=0;
puts("请输入一串字符：");
gets(ch); /*提示：使用字符串输入函数*/
for(i=0;i<strlen(ch);i++)
if(('a'<=ch[i]&&ch[i]<='z')||('A'<=ch[i]&&ch[i]<='Z'))
count++;
printf("字母个数为：%d \n", count);
}

Answer 2

#include <stdio.h>void main(){ int letter, space, digit, other; char ch; letter = space = digit = other = 0; while ((ch = getchar ()) != '\n') { if (ch>='a' && ch <= 'z' || ch>='A'&&ch<='Z') letter++; } printf ("字母：%d\n", letter);

Answer 3

C语言字符串的学习，输入指定字符串，并且计算字符串的位数