Question

一道C++编程题，请高手帮我看看我的答案对吗？

仅使用条件运算符确定输入的整数是否是20或小于20；大于20且不大于30；大于30但不超过100；或者大于100。
我的答案：
＃include<iostream>
using namespace std;
int main(){
int a=0;
cout<<“Enter a number:”;
cin>>a;
cout<<endl<<(a>100?“a is greater than 100.”:(a>30?“a is greater than 30 and is less than 100.”:(a>20?“a is greater than 20 and is less than 30.”:(a<20?“a is less than 20.”:“a is 20.”))));
return 0;
}

Answer 1

思想是对的 不过强烈建议入门一定要养成良好的编程习惯和风格！！！

#include<iostream>
using namespace std;
int main(){
int a=0;
cout<<"Enter a number:";
cin>>a;
cout<<endl;
cout<<(a>100?
"a is greater than 100."
:(a>30?
"a is greater than 30 and is less than 100."
:(a>20?
"a is greater than 20 and is less than 30."
:(a<20?
"a is less than 20."
:"a is 20."
)
)
)
);
return 0;
}

Answer 2

对的，要把“和”换成"，＃include<iostream> 的‘#’换成#

Answer 3

是对的，但是编的可读性极差，貌似有显摆的嫌疑，这样对以后的提高不好，编C＋＋一定要注重可读性，可操作性。

Answer 4

对的

Answer 5

搞不懂