已知x²-2=0,则代数式(如图所示)的值是？ (要具体步骤)
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已知x²-2=0,则代数式(如图所示)的值是1.
解：
x^2= 2
(x-1)^2/(x^2-1) + x^2/(x+1)
=(x-1)/(x+1) +x^2/(x+1)
= (x^2+x-1)/(x+1)
= (x+1)/(x+1)
=1
解：
x^2= 2
(x-1)^2/(x^2-1) + x^2/(x+1)
=(x-1)/(x+1) +x^2/(x+1)
= (x^2+x-1)/(x+1)
= (x+1)/(x+1)
=1
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x^2= 2
(x-1)^2/(x^2-1) + x^2/(x+1)
=(x-1)/(x+1) +x^2/(x+1)
= (x^2+x-1)/(x+1)
= (x+1)/(x+1)
=1
(x-1)^2/(x^2-1) + x^2/(x+1)
=(x-1)/(x+1) +x^2/(x+1)
= (x^2+x-1)/(x+1)
= (x+1)/(x+1)
=1
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x^2= 2
(x-1)^2/(x^2-1) + x^2/(x+1)
=(x-1)/(x+1) +x^2/(x+1)
= (x^2+x-1)/(x+1)
= (x+1)/(x+1)
=1
(x-1)^2/(x^2-1) + x^2/(x+1)
=(x-1)/(x+1) +x^2/(x+1)
= (x^2+x-1)/(x+1)
= (x+1)/(x+1)
=1
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X²=2
x=±根\(^o^)/~2
x=±根\(^o^)/~2
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