Question

lua语言一个数组的问题。

function minzhi()
local days={"1","2","3","4","5","6","7","8","9","0","a","b","c","d","e","f","g","h","j","k","l","q","w",
"e","r","t","y","u","i","o","p","z","x","c","v","b","n","m"}
end
print (minzhi())
如何让函数每次运行，从第一个数组开起输出，一直到最后一个，又从第一个输出，这样循环显示

Answer 1

用 closure 最简单，比如下面的代码，每次调用 minzhi() 都会打印 days 里的元素。

function newMinzhi()
    local days={"1","2","3","4","5","6","7","8","9","0","a","b","c","d","e","f","g","h","j","k","l","q","w",
        "e","r","t","y","u","i","o","p","z","x","悄历c","v","b","n"旅没,"m"}
    local idx = 1
    return function ()
        if idx > #days then
            idx = 1
        end
        print(days[idx])
        idx = idx + 1
    end
end

minzhi = newMinzhi()
minzhi()   -- 打印 1
minzhi()   -- 打印 2
minzhi()   -- 打印启镇搜 3
................

追问

下面显示的怎么都是楼字，和英文。中文是字符串。要怎么弄。直接调用这个函数。可以用的。

追答

-- 之前的版本直接把内容打印出来了，现在的版本改成返回 days 中的值。

function newMinzhi()
    local days= {"中", "国"}
    local idx = 1
    return function ()
        if idx > #days then
            idx = 1
        end
        local ret = days[idx]
        idx = idx + 1
        return ret
    end
end
minzhi = newMinzhi()
print(minzhi())
print(minzhi())