Question

javascript ajax 传递参数问题

function KeyUp() {
var str = document.getElementById("txt").innerHTML;
var url = "ajax.ashx?p=" + str;
var ajax = GetXmlHttpObject();
ajax.onreadystatechange = function () {
if (ajax.readyState == 4) {
document.getElementById("sp").innerHTML=ajax.responseText;
}

}
ajax.open("post",url,true);
ajax.send(null);
}
为什么我的参数p不能够传递过去，要是改成var url = "ajax.ashx?p=123";就能够返回，求大神解答

Answer 1

var str = document.getElementById("txt").innerHTML;

明显是这一行没取到值

追问

名字：

这是后面的代码

追答

var str = document.getElementById("txt").innerHTML;

改成
var str = document.getElementById("txt").value;