Question

C语言程序 统计成绩并拍名次 怎么写程序 用C不用C++

70个学生分别统计3门功课的 优秀 良 中 及格 不及格 人数
低于30不能补考 统计补考人数 不能补考人数
求出每个同学 平均成绩 精确小数点后一位
对70名同学的成绩排序 注意并列名次
学生的名字用如下方法随即产生
char f_name[4][3]={“赵”，“钱”，“孙”，“李”}
char s_name[][]={}
char cname[20]
for(int j=0;j<4;j++)
for(int k=0;k<5;k++)
cname[j*k+k]=strcat(f_name[j],s_name[k])
好的可以另加分

Answer 1

#include<stdio.h>
#include<stdlib.h>
#include<math.h>
#include<string.h>
#include<time.h>
//
int const N=70;

struct Boy{
char name[20];
int c1;
int c2;
int c3;
};
typedef struct Boy boy;
boy classmate[N];
char *names[]={"Charles","Mark","Bill","Vincent","William","Joseph"
,"James","Henry","Gary","Martin","Fred","Gary","William",
"Charles","Michael","Karl","Bob","John","Thomas","Dean",
"Paul","Jack","Brooke","Kevin","Louis","John","George",
"Henry","Benjamin","Robert","Carl","Scott","Tom","Eddy",
"Kris","Peter","Johnson","Bruce","Robert","Peter","Bill",
"Joseph","John","Burt","Charlie","Elliot","George","Johnson",
"Richard","James","Charles","Bruce","David","Nick","Walt",
"John","Mark","Sam","Davis","Neil","Carl","Lewis","Billy",
"Richard","Howard","Allen","Johnny","Robert","Martin","Jeff",
"Paul","Sam","Francis","Lewis","Stephen","Andy","Scott","Albert",
"Kevin","Michael","Taylor","Jackson","Jack","Jimmy","Allen",
"Martin","Vincent"};

void s(int s,int c);
void initname(boy * mem,int num);
void initscore(boy * mem,int num);
void count (boy * mem,int n);

static struct {
int good;
int med;
int ok;
int bad;
int out;
} stat[3];

int main(int argc, char *argv[]){
initname(classmate,N);
initscore(classmate,N);
count (classmate,N);
printf("%5s%5s%5s%5s%5s%5s\n","","good","med","ok","bad","out");
printf("%-5s%5d%5d%5d%5d%5d\n","c1:",
stat[0].good, stat[0].med,
stat[0].ok,stat[0].bad,
stat[0].out );
printf("%-5s%5d%5d%5d%5d%5d\n","c2:",
stat[1].good, stat[1].med,
stat[1].ok,stat[1].bad,
stat[1].out );
printf("%-5s%5d%5d%5d%5d%5d\n","c3:",
stat[2].good, stat[2].med,
stat[2].ok,stat[2].bad,
stat[2].out );
system("PAUSE");

return EXIT_SUCCESS;
}

void initname(boy * mem,int num){
int i=0;
char **np=names;
for (;i<num;i++){
strcpy ( (mem++)->name,*(np++));
}

}

void initscore(boy * mem,int num){
//初始化成绩，完全随机。
int i=0;
int n=100;
srand( time(NULL) );
for ( i=0; i<num; i++ ){

mem->c1=(int)(n*rand()/(RAND_MAX+1.0));

mem->c2=(int)(n*rand()/(RAND_MAX+1.0));

mem->c3=(int)(n*rand()/(RAND_MAX+1.0));
mem++;
}
}
void count (boy * mem,int n){
// >=85 good
// >=70 med
// >=60 ok
// >=30 bad
// <30 out
int i;
for ( i=0; i<n; i++ ){
printf("%d %d %d\n",mem->c1,mem->c2,mem->c3);
s(mem->c1,0);
s(mem->c2,1);
s(mem->c3,2);
mem++;
}
}
void s(int s,int c){
// >=85 good
// >=70 med
// >=60 ok
// >=30 bad
// <30 out
if (s>=85){
stat[c].good++;
}
else if(s>=70){
stat[c].med++;
}
else if(s>=60){
stat[c].ok++;
}
else if(s>=30){
stat[c].bad++;
}
else {
stat[c].out++;
}//endif
}

追问

没有那个 名次的排序啊

追答

给你的代码我编译过了，xp sp3 32 bit ,dev c++ 4.9.9.2.
void sort_print(boy* mem,int num){
qsort(classmate,N,sizeof(boy),cmp);
int i=0;
printf("\n\n%10s%5s%5s%5s%5s\n","name","c1","c2","c3","sum");

for (;isum > a2->sum)
return 1;
if (a1->sum sum)
return -1;
return 0;
}
你加上这两个函数。调用sort_print(classmate,N);就可以了。