先化简，再求值.x+2分之x-x+2分之x平方+2x+1除以x-1分之x平方
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解：原式=x/(x+2)-(x^2+2x+1)/(x+2)÷x^2/(x-1)
=x/(x+2)-(x+1)^2/(x+2)*(x-1)/x^2
=x/(x+2)-(x+1)^2(x-1)/x^2(x+2)
=x^3/x^2(x+2)-(x+1)^2(x-1)/x^2(x+2)
=【x^3-(x+1)^2(x-1)】/x^2(x+2)
=(x^3-x^3-x^2+x+1)/x^2(x+2)
=-(x^2-x-1)/x^2(x+2)
=x/(x+2)-(x+1)^2/(x+2)*(x-1)/x^2
=x/(x+2)-(x+1)^2(x-1)/x^2(x+2)
=x^3/x^2(x+2)-(x+1)^2(x-1)/x^2(x+2)
=【x^3-(x+1)^2(x-1)】/x^2(x+2)
=(x^3-x^3-x^2+x+1)/x^2(x+2)
=-(x^2-x-1)/x^2(x+2)
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