Question

[根号下54-根号6分之1-2倍根号2分之1]＋根号下32-2分之1倍根号下24？

Answer 1

答：
2倍根号3分之2-3倍根号2分之3＋根号24
=2√(2/3)-3√(3/2)+√24
=2√(6/9)-3√(6/4)+√(4*6)
=(2/3)√6-(3/2)√6+2√6
=(2/3-3/2+2)√6
=7√6 / 6
[3倍根号下2分之1-5倍根号下3分之1]-2倍根号下8分之1-根号下20
=3√(1/2)-5√(1/3)-2√(1/8)-√20
=(3/2)√2-(5/3)√3-(1/2)√2-2√5
=√2-(5/3)√3-2√5,2,[根号下54-根号6分之1-2倍根号2分之1]＋根号下32-2分之1倍根号下24
2倍根号3分之2-3倍根号2分之3＋根号24
[3倍根号下2分之1-5倍根号下3分之1]-2倍根号下8分之1-根号下20