Question

第十题，求极限和步骤，谢谢了！

Answer 1

=lim(x→0) x/tan(2x)
=lim(x→0) 1/[2sec²(2x)]
=lim(x→0) cos²(2x)/2
=1/2
原式=lim(x→0) (2x)/tan(2x)*(1/2)
=1/2

追答

Answer 2

原式==lim(x→0) x/tan(2x)
==lim(x→0) xcos2x/sin(2x)
=1/2 ×lim(x→0)(2x)/sin(2x) ×lim(x→0)cos2x
=1/2 ×1×1
=1/2