Question

求C语言程序设计题答案：x[7]={2,3,9,76,45,23,42},编程实现数组x中奇数的个数及奇数之和。

为了自考网上答题的综合作业题，跪求答案。

Answer 1

#include <stdio.h>
#define MAX 7
int main(int argc, char *argv[])
{
int x[MAX]={2,3,9,76,45,23,42},i,j,sum,t;
for(i=j=sum=0;i<MAX;++i){
t=x[i]/2;
(t*2!=x[i])?++j,sum+=x[i]:NULL;
}
printf("奇数个数:%d\n奇数之和:%d\n",j,sum);
return 0;
}

Answer 2

#include<stdio.h>
void main()
{
int i;
int m = 0;
int sum = 0;
int x[7]={2,3,9,76,45,23,42};
for(i = 0; i < 7; i++)
{
if(x[i] % 2 == 1)
{
m++;
sum += x[i];
}
}
printf("奇数的个数为%d，奇数的和为%d\n",m,sum);
}

Answer 3

#include <stdio.h>
#include <conio.h>
void main()
{
int x[7]={2,3,9,76,45,23,42};
int i,s = 0,h=0;
for ( i=0; i<7; i++)
{
if (x[i] % 2 == 1)
{
s = s + b[i];
h++;
}
}
printf("The odd is :%d\n",s);
printf("The num is :%d\n",h);
}
没有验证

Answer 4

int m = 0;
int sum = 0;
int x[7]={2,3,9,76,45,23,42};
for(i = 0; i < 7; i++){
if(x[i] % 2 ！=0)
{
m++;
sum =sum+ x[i];
}
}
printf("奇数的个数为%d，奇数的和为%d\n",m,sum);