问几道数学题，要过程，谢谢
(-2008)^2÷(1/2)^3-(-3-π^0)^2(-a^3)^3÷[(-a^2)×(-a^3)^2](x^m)^2×x^22(x^3)^4-5(x^6)^2(x-...
(-2008)^2÷(1/2)^3-(-3-π^0)^2 (-a^3)^3÷[(-a^2)×(-a^3)^2] (x^m)^2×x^2
2(x^3)^4-5(x^6)^2 (x-y)^2×[(y-x}^3]^3 展开
2(x^3)^4-5(x^6)^2 (x-y)^2×[(y-x}^3]^3 展开
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1，(-2008)^2÷(1/2)^3-(-3-π^0)^2
=2008^2*8-16
2，(-a^3)^3÷[(-a^2)×(-a^3)^2]
=-a^9/-a^2*a^6
=a
3，(x^m)^2×x^2
=x^(2m)*x^2=x^(2m+2)
4，2(x^3)^4-5(x^6)^2
=2*x^12-5*x^12
=-3x^12
5，(x-y)^2×[(y-x}^3]^3
=(x-y)^2*（y-x）^9
=-(x-y)^11
=2008^2*8-16
2，(-a^3)^3÷[(-a^2)×(-a^3)^2]
=-a^9/-a^2*a^6
=a
3，(x^m)^2×x^2
=x^(2m)*x^2=x^(2m+2)
4，2(x^3)^4-5(x^6)^2
=2*x^12-5*x^12
=-3x^12
5，(x-y)^2×[(y-x}^3]^3
=(x-y)^2*（y-x）^9
=-(x-y)^11
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