因式分解：2x^4-x^3+6x^2-x+6
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2x4-x3-6x2-x+2
=x^2(2x^2-x-6)-(x-2)
=x^2(2x+3)(x-2)-(x-2)
=(x-2)[x^2(2x+3)-1]
=(x-2)(2x^3+3x^2-1)
=(x-2)[(2x^3+2x^2)+(x^2-1)]
=(x-2)[2x^2(x+1)+(x+1)(x-1)]
=(x-2)(x+1)(2x^2+x-1)
=(x-2)(x+1)(2x-1)(x+1)
=(x+1)^2(x-2)(2x-1)
=x^2(2x^2-x-6)-(x-2)
=x^2(2x+3)(x-2)-(x-2)
=(x-2)[x^2(2x+3)-1]
=(x-2)(2x^3+3x^2-1)
=(x-2)[(2x^3+2x^2)+(x^2-1)]
=(x-2)[2x^2(x+1)+(x+1)(x-1)]
=(x-2)(x+1)(2x^2+x-1)
=(x-2)(x+1)(2x-1)(x+1)
=(x+1)^2(x-2)(2x-1)
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