求由曲面x2+y2=az，柱面x2+y2=ay(a＞0)以及平面z=0所围的立体体积．
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【答案】：该立体在坐标面z=0上的投影区域为D：x2+y2≤ay，故
style='FONT-SIZE: 14px; FONT-FAMILY: zuoyeFont_mathFont, 'Microsoft Yahei', 宋体, sans-serif; WHITE-SPACE: normal; TEXT-TRANSFORM: none; WORD-SPACING: 0px; FLOAT: none; FONT-WEIGHT: normal; COLOR: rgb(51,51,51); FONT-STYLE: normal; ORPHANS: 2; WIDOWS: 2; DISPLAY: inline !important; LETTER-SPACING: normal; BACKGROUND-COLOR: rgb(255,255,238); TEXT-INDENT: 0px; font-variant-ligatures: normal; font-variant-caps: normal; -webkit-text-stroke-width: 0px'>体积=(π/8-1/6)a^3
style='FONT-SIZE: 14px; FONT-FAMILY: zuoyeFont_mathFont, 'Microsoft Yahei', 宋体, sans-serif; WHITE-SPACE: normal; TEXT-TRANSFORM: none; WORD-SPACING: 0px; FLOAT: none; FONT-WEIGHT: normal; COLOR: rgb(51,51,51); FONT-STYLE: normal; ORPHANS: 2; WIDOWS: 2; DISPLAY: inline !important; LETTER-SPACING: normal; BACKGROUND-COLOR: rgb(255,255,238); TEXT-INDENT: 0px; font-variant-ligatures: normal; font-variant-caps: normal; -webkit-text-stroke-width: 0px'>体积=(π/8-1/6)a^3
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