计算:√xy+√x/y-√y /x+√(x/y+y/x+2) x＞0，y＞0
展开全部
:√xy+√x/y-√y /x+√(x/y+y/x+2)
=√xy+1/y√xy-1/x√xy+√(x²+y²+2xy)/xy
=√xy+1/y√xy-1/x√xy+√(x+y)²/xy
=√xy+1/y√xy-1/x√xy+(x+y)/xy√xy
=√xy+1/y√xy-1/x√xy+1/y√xy+1/x√xy
=√xy+2/y√xy
=√xy+1/y√xy-1/x√xy+√(x²+y²+2xy)/xy
=√xy+1/y√xy-1/x√xy+√(x+y)²/xy
=√xy+1/y√xy-1/x√xy+(x+y)/xy√xy
=√xy+1/y√xy-1/x√xy+1/y√xy+1/x√xy
=√xy+2/y√xy
追问
√(x+y)²/xy=(x+y)/xy√xy？
追答
√(x+y)²/xy=(x+y)/xy√xy
是的
已赞过
已踩过<
评论
收起
你对这个回答的评价是？
推荐律师服务：
若未解决您的问题，请您详细描述您的问题，通过百度律临进行免费专业咨询
