数学 过程 谢谢
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原式=(x-3)/(x+3)^2-x/(x+3)(x-3)
=[(x-3)(x+3)-x(x+3)]/(x+3)^2(x-3)
=(x^2-9-x^2-3x)/(x+3)^2(x-3)
=(-3x-9)/(x+3)^2(x-3)
=-3(x+3)/(x+3)^2(x-3)
=-3/(x+3)(x-3)
=-3/(x^2-9)
=[(x-3)(x+3)-x(x+3)]/(x+3)^2(x-3)
=(x^2-9-x^2-3x)/(x+3)^2(x-3)
=(-3x-9)/(x+3)^2(x-3)
=-3(x+3)/(x+3)^2(x-3)
=-3/(x+3)(x-3)
=-3/(x^2-9)
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