Question

因式分解(x^2+y^2)(x^2+y^2-4)+4

4ab^2-4a^2b-b^3

Answer 1

(x^2+y^2)(x^2+y^2-4)+4
=(x²+y²)²-4(x²+y²)+4
=[(x²+y²)-2]²
=(x²+y²-2)²

4ab^2-4a^2b-b^3
=-b(-4ab+4a²+b²)
=-b(2a-b)²

Answer 2

(x^2+y^2)(x^2+y^2-4)+4
=(x^2+y^2)^2-4(x^2+y^2)+4
=(x^2+y^2-2)^2

4ab^2-4a^2b-b^3
=-b(4a^2-4ab+b^2)
=-b(2a-b)^2