数学题，谢谢
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2sin(A/2)^2 = sinA
2sin(A/2)^2 = 2sin(A/2)cos(A/2)
sin(A/2) = cos(A/2)
A = π/2
sin(B-C) = sinBcosC - cosBsinC = 2cosBsinC
sinBcosC = 3cosBsinC
tanB = 3 tanC
C = π/2 - B
tanB = 3/tanB
tanB = sqrt(3)
B = π/3, C = π/6
AC/AB = tanB = sqrt(3)
2sin(A/2)^2 = 2sin(A/2)cos(A/2)
sin(A/2) = cos(A/2)
A = π/2
sin(B-C) = sinBcosC - cosBsinC = 2cosBsinC
sinBcosC = 3cosBsinC
tanB = 3 tanC
C = π/2 - B
tanB = 3/tanB
tanB = sqrt(3)
B = π/3, C = π/6
AC/AB = tanB = sqrt(3)
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这是真学霸啊👍
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