第十四题啊啊啊啊 求教
1个回答
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(1)9^(1/3)
=(2^3+1)^(1/3)
≈2+1/(3*2^2)
=2+1/12
=25/12
(2)80^(1/4)
=(3^4-1)^(1/4)
≈3-1/(4*3^3)
=3-1/36
=107/36
(3)100^(1/7)
=(2^7-28)^(1/7)
≈2-28/(7*2^6)
=2-1/16
=31/16
(4)1000^(1/10)
=(2^10-24)^(1/10)
≈2-24/(10*2^9)
=2-3/640
=1277/640
=(2^3+1)^(1/3)
≈2+1/(3*2^2)
=2+1/12
=25/12
(2)80^(1/4)
=(3^4-1)^(1/4)
≈3-1/(4*3^3)
=3-1/36
=107/36
(3)100^(1/7)
=(2^7-28)^(1/7)
≈2-28/(7*2^6)
=2-1/16
=31/16
(4)1000^(1/10)
=(2^10-24)^(1/10)
≈2-24/(10*2^9)
=2-3/640
=1277/640
追问
😆求求证过程
追答
求证过程书上的提示写得很清楚了
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