Question

用C++编写一个洗牌发牌的函数，玩家可能有两个、三个和四个。将牌存到数组中

Answer 1

#include <stdio.h>
#include <time.h>

#define SIZE 54

int nArray[SIZE];

void Shuffle()
{
int i, temp, randnum;
srand(time(0));
for (i = 0; i < SIZE; i++)
{
randnum = rand() % SIZE;
temp = nArray[i];
nArray[i] = nArray[randnum];
nArray[randnum] = temp;
}
}

int main()
{
int i, n;
printf("人数：");
scanf("%d", &n);
for (i = 0; i < SIZE; i++)
{
nArray[i] = i;
}
Shuffle();
for (i = 0; i < SIZE; i++)
{
if (i % (SIZE / n) == 0)
{
printf("\n第%d个人：", i / (SIZE / n));
}
printf("%2d ", nArray[i]);
}
return 0;
}